A1.6kg particle moves in a circle of radius3.5m. As you look down on the plane o
ID: 2183335 • Letter: A
Question
A1.6kg particle moves in a circle of radius3.5m. As you look down on the plane of its orbit, the particle is initially moving clockwise. If we call the clockwise direction positive, the particle's angular momentum relative to the center of the circle varies with time according toL(t) = 10 N ms - (6.0N m)t.
A1.6kg particle moves in a circle of radius3.5m. As you look down on the plane of its orbit, the particle is initially moving clockwise. If we call the clockwise direction positive, the particle's angular momentum relative to the center of the circle varies with time according toL(t) = 10 N ½ m½s - (6.0N ½ m)t. (a) Find the magnitude and direction of the torque acting on the particle. 6.0Explanation / Answer
integrating angular momentum= I = mr^2 = 10-6t
= 10/mr^2 - 6/mr^2t
A = 0.510 ,and B = -0.306