Two billiard balls of equal mass move at right angles and meet at the origin of
ID: 2185697 • Letter: T
Question
Two billiard balls of equal mass move at right angles and meet at the origin of an coordinate system. Ball A is moving upward along the axis at = 1.6 , and ball B is moving to the right along the axis with speed = 4.4 . After the collision, assumed elastic, ball B is moving along the positive axis(Figure 1) . Part A What is the final direction of ball A? Express your answer using two significant figures. = clockwise from the -direction SubmitMy AnswersGive Up Part B What are their two speeds? Express your answers using two significant figures. Enter your answers numerically separated by a comma. , = SubmitMy AnswersGive Up Provide FeedbackContinue Figure 1 of 1Explanation / Answer
Two billiard balls of equal mass move at right angles and meet at the origin of an xy coordinate system. Initially ball A is moving upward along the y axis at 2.0 m/s nd ball B is moving to the right along the x axis with speed 3.7 m/s . After the collision (assumed elastic), the second ball is moving along the positive y axis What is the final direction/angle of ball A? What are the speeds of the two balls? finall let the components of velocity of a be vx and vy along positive x and y axes.and let Ball be move with velocity v1 along +ve y axis(given) conserve momentum along y axis 2m = mv1 + mvy 2= v1+vy----------1 conserve slong x axis 3.7m= m vx 3.7= vx----------2 conserving KE 3.7^2 + 2^2= v1^2 + vx^2 + vy^2 4=v1^2 + vy^2-----------3 (put vx=3.7) using 1 and 3 4= (2-vy)^2 +vy^2 4=4-4vy+2vy^2 2vy=vy^2 vy=2 or vy=0 but vy cannot be 2 because then v1 would become zero that is ball b comes to rest not possible(given in question ball b moves up after colliding) so vy=0 v1=2 using (1) so ball A's final velocity = 3.7m/s along +X axis and ball B's = 2 m/s along +y axis