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In the figure below, R1 = 14.0 k, R2 = 19.0 k, C = 0.600 F, and the ideal batter

ID: 2187755 • Letter: I

Question

In the figure below, R1 = 14.0 k, R2 = 19.0 k, C = 0.600 F, and the ideal battery has emf = 20.0 V. First, the switch is closed a long time so that the steady state is reached. Then the switch is opened at time t = 0. What is the current in resistor 2 at t = 4.00 ms?

In the figure below, R1 = 14.0 k, R2 = 19.0 k, C = 0.600 F, and the ideal battery has emf = 20.0 V. First, the switch is closed a long time so that the steady state is reached. Then the switch is opened at time t = 0. What is the current in resistor 2 at t = 4.00 ms?

Explanation / Answer

potential when switch is closed = 11.5151V. this V can support a maximum of 6.9x10^-6 coloumb charge in capacitor. when the switch is open we get a time constant of 0.0114 = 11.4ms so I = Io(1 - exp(-t/Time)) put all the value to get1.7935x10^-4 amps. here Io = 11.5151/19Kohms