Consider two parallel-plate capacitors that are connected in parallel as shown i

Question

Consider two parallel-plate capacitors that are connected in parallel as shown in Figure 2. The capacitors are identical except for the dielectric material in C1. A potential difference of 150 V is applied across the terminals A and B, and then the source of potential difference is removed. (a) Find the charge on each capacitor. (b) Find the total energy stored in the capacitors. (c) If the dielectric material is now removed from C1, determine the total energy stored in the capacitors. (d) Find the total voltage across the terminals A and B

Explanation / Answer

why would you have two C1s? I'll relabel the one on the right C3, and the 6uf one as C4. All C and Qs in micro Farads and coulombs. C2 and C4 are in parallel and the capacitance is 19.6 (call it C24) C1 and C3 are in series, as is the C2/4 equivalent, and they are all 19.6 so the total equivalent is 19.6/3 = 6.53 Total Q = CV = 6.53 x 9 = 58.8 this charge is on C1, C3, and C24 Since the 3 are equal, voltage divides equally to 3 volts on each, C1, C3, and C24. Charge on C2: Q = Cv = 3*13.6 charge on C4 Q = CV = 3*6

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