A certain spring stores 10.6J of potential energy when it is stretched by 2.80cm

Question

A certain spring stores 10.6J of potential energy when it is stretched by 2.80cm from its equilibrium position.

1.How much potential energy would the spring store if it were stretched an additional 2.80cm ?
2.How much potential energy would it store if it were compressed by 2.80cm from its equilibrium position?
3.How far from the equilibrium position would you have to stretch the string to store 21.2J of potential energy?
4.What is the force constant of this spring?


please detail your work! not just answer

Explanation / Answer

pE= 0.5kx2 ;

11 = 0.5*K*0.02752;

so K = 2.909 N/cm2 ------------>answer 4;

now use the same formula where every value is known except x;

find it out

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