Steam at 100oC is added to ice at0oC. (a) Mass of ice (mi ) = 0.050kg Latent Heat of ice ( L i ) = 333000 J / kg Total heat for the melting of iceQi = mi * Li = 16650 J Mass of steam ( m s ) = 0.010 kg Latent Heat of steam ( L s ) = 2256000 J /kg Temp. of steam ( t s ) = 100 C0 Total heat comes from steam Qs = ( m s) *( L s ) = 22560 J Since Qs >Qi So all ice willmelt and the temperature will increase upto toC Temp. difference of water ( D t ) = t C0 spec.heat capacity of water(Cw ) = 4190 J / kg- K Apply ; Principle ofCalorimetry Qi+ m i cw ( D t) = Qs Calculate the value of ' t' (b)-------------------------------------------------- Mass of ice (mi ) = 0.050kg Latent Heat of ice ( L i ) = 333000 J / kg Total heat for the melting of iceQi = mi * Li = 16650 J Mass of steam ( m s ) = 0.001 kg Latent Heat of steam ( L s ) = 2256000 J /kg Temp. of steam ( t s ) = 100 C0 Total heat comes from steam Qs = ( m s) *( L s ) = 2256 J Since Qs