Consider three engines that each use 1680 J of heat from a hot reservoir (temper

Question

Consider three engines that each use 1680 J of heat from a hot reservoir (temperature = 560 K). These three engines reject heat to a cold reservoir (temperature = 335 K). Engine I rejects 1005 J of heat. Engine II rejects 1203 J of heat. Engine III rejects 655 J of heat. One of the engines operates reversibly, and two operate irreversibly. However, of the two irreversible engines, one violates the second law of thermodynamics and could not exist. For each of the engines determine the total entropy change of the universe, which is the sum of the entropy changes of the hot and cold reservoirs. On the basis of your calculations, identify which engine operates reversibly, which operates irreversibly and could exist, and which operates irreversibly and could not exist. (Round off to two decimal places.)

?S(J/K)Type of operationEngine I---Select---reversibleirreversible, could existirreversible, could not existEngine II---Select---reversibleirreversible, could existirreversible, could not existEngine III ---Select---reversibleirreversible, could existirreversible, could not exist

Explanation / Answer

Consider Carnot Heat Engine operating between 545 K and 335 K : --------------------------------------… E sub THC = E sub THMAX = TH - TL / TH E sub THC = E sub THMAX = 560 - 335 / 560 = 0.4017 = 40.17 %

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