A bullet (m = 0.0270 kg) is fired with a speed of 92.00 m/s and hits a block (M
ID: 2217527 • Letter: A
Question
A bullet (m = 0.0270 kg) is fired with a speed of 92.00 m/s and hits a block (M = 2.30 kg) supported by two light strings as shown, stopping quickly. Find the height to which the block rises. Find the angle (in degrees) through which the block rises, if the strings are 0.540 m in length.
A bullet (m = 0.0270 kg) is fired with a speed of 92.00 m/s and hits a block (M = 2.30 kg) supported by two light strings as shown, stopping quickly. Find the height to which the block rises. Find the angle (in degrees) through which the block rises, if the strings are 0.540 m in length.Explanation / Answer
common velocity of both after hitting v = (0.27*92)/(0.27+2.3) = 9.665 m/s height reacehed = h 0.5* (0.27+2.3) * 9.665*9.665 = (0.27+2.3)*9.8*h h = 4.7662 m