I\'m really not understanding how to approach this problem. Newton\'s gravity eq
ID: 2219425 • Letter: I
Question
I'm really not understanding how to approach this problem. Newton's gravity equation F=G(m1m2/r2) leads directly to Kepler's 3 laws. The electric force equation looks very similar F F=k(q1q2/r2) , consider a classical hydrogen atom (i.e. no quatum mechanics) (mp>>me). Which of Kepler's 3 laws would apply to the atom? Would the oribit of the elecron be an ellipse? Would it trace out equal areas over equal time? What law would replace the law of periods (you may assume a circular orbit for this derivation). I'm guessing that since the two equations look virtually identical, all the laws would be the same? I'm just not sure at allExplanation / Answer
The elliptical shape of the orbit is a result of the inverse square force of gravity. As one of the fields which obey the general inverse square force of gravity. showing that the acceleration of gravity, g, is an expression of the intensity of the gravity field 4GM/4r^2= I= GM/r2=g. so The law of periods will follows the Kepler's Law of Periods i.e T^2 = 4^2*a^3/G(mp+me). a.= astronautical unit. you may neglect the size of electron because mp>>me so apply mathematical approximation. if data of me is given so neglect the value of me. All three rules of Kepler will apply here.