Cars A and B are racing each other along the same straight road in the following

Question

Cars A and B are racing each other along the same straight road in the following manner: Car A has a head start and is a distance Da beyond the starting line at y=0. The starting line is at x=0. Car A travels at a constant speed Va. Car B starts at the starting line but has a better engine than Car A, and thus Car B travels at a constant speed Vb, which is greater than Va. 1)How long after Car B started the race will Car B catch up with Car A? 2)How far from Car B's starting line will the cars be when Car B passes Car A?

Explanation / Answer

Part A) time = (distance /velocity) = Da / (Vb – Va). Part B) Distance traveled by B in time t[Da / (Vb – Va)] = Vb* Da / (Vb – VA) (use the appropiate case sensitive variables of course v_B not just Vb)

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