A meter-stick with a small hole drilled at the 20-cm mark is suspended by a stri

Question

A meter-stick with a small hole drilled at the 20-cm mark is suspended by a string through that hole. A downward force of 2.94 N is applied at the 5.0-cm mark, in order to balance the other forces and make the meter stick level, without moving. (A) Find the mass of the meter stick. Hint: you should treat the mass of the meter stick as if it is all concentrated in the middle, at the 50-cm mark. Draw a free-body diagram to help. Putting the pivot-point at the sting's position will eliminate that force from your torque equation. Give the answer in kg. 1 kg. (B) Find the force exerted by the string. Keep three significant figures. 2 N

Explanation / Answer

let tension in string be T. weight be m*g; then T=mg+2.94 from torque about the mid point, T*(0.5-.2)=2.94*(0.5-0.05) T=4.41 N so mg=4.41-2.94=1.47 N so m=0.15 kg

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