In the figure below, the rolling axle, 1.70 m long, is pushed along horizontal r

Question

In the figure below, the rolling axle, 1.70 m long, is pushed along horizontal rails at a constant speed v = 3.36 m/s.A resistor R = 0.380 ohm is connected to the rails at points a and b, directly opposite each other. (The wheels make good electrical contact with the rails, and so the axle, rails, and R form a closed-loop circuit. The only significant resistance in the circuit is R.) There is a uniform magnetic field B = 0.0875 T vertically downward. A) Calculate the induced current I in the resistor. B) What horizontal force F is required to keep the axle rolling at constant speed? C) Calculate the potential at point b relative to point a. The image is located here: http://dropcanvas.com/yni1c/1

Explanation / Answer

so here we can find that the rate of change of area =1.70*3.36m/s=5.712m^2/s

rate of change of flux=0.0875*5.712=0.4998

so the emf generated =0.4998/0.380=1.315A

C) potential of point b raletive to a=-0.4998V

b)horizontal force required=i*l*B=1.315*1.70*0.0875=0.195N

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