I need to know the formulas and the step-by-step answers for the following physi

Question

I need to know the formulas and the step-by-step answers for the following physics questions: 1. You throw a ball upward with an initial speed of 7.0 m/s, and it returns to your hand o.92 seconds later, (assuming air resistance can be ignored). (a) What is the average acceleration vector of the ball? (b) Find the highest up ward distance that ball can get. 2. A ball was thrown at an angle of 45.0 degrees above the horizontal, that it traveled a horizontal distance of 496ft, and that it was caught at the same level from which it was thrown. (a) What was the ball's initial speed? (b) How long was the ball in the air?

Explanation / Answer

1. a) Acceleration is always constant...i.e a = 9.81 m/s^2 in downward direction.

So, avg acceleration vector, a = [-9.81 m/s^2] ^j

b) At highest distance..all the KE has converted to PE:

0.5 * m * v^2= m * g * h

S0, h = v^2 / 2g = 2.497 m

2)

a) R = V^2 * sin {2*theta} / g

Here R = 496 ft = 151.18 m

So, V = 38.51 m/s

T = 2 * V sin theta / g = 5.55 sec

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