Please solve this and find the value of X A 1400 kg car moving at 18 m/s approac
ID: 2240728 • Letter: P
Question
Please solve this and find the value of X
Explanation / Answer
tunneling probability T = e^-2kL
where k =2*pie* sqrt[2m(U-E)]/h
so according to your question
X =-4*pie*sqrt[2m(U-E)]*L/h
where h is plankc constant.
the gravitational potential is
U=-GM/(r+h)
where r is radius of the earth and h is the height of the hill
U=6.25*10^7
E=(mv^2)/2
= 2.2*10^5
hence U-E= 62.28*10^6
k=2*3.14*sqrt[2*1400*62.28*10^6]/6.626*10^-34
=2*3.14*417593/6.626*10^-34
=3.95*10^39
X=-2kL
=-2*3.95*10^39*31
=-2.449*10^41