I need help with the following assignment in C#. Suppose x, y, and z are int var

Question

I need help with the following assignment in C#.

Suppose x, y, and z are int variables and x=12, y=34, and z=18. Determine if the following are true to false.

True or False?

!(x – y >= 1)

z <= 7 || y < 12

(x + y != 40) && (x != z)

(z – x >= y) || (y – x != z + 4)

(5 – x <= 2 * y) && (y – 15 >= z) || (x – 5 != y – 2 * z)

What text would be displayed in the label if the following code was run?

int count = 5;
lblTest.Text = “”;
while (count-- > 0)
     lblTest.Text += count + “ ”;

What text would be displayed in the label if the following code was run?

int num = 1;
lblTest.Text = “”;
for (int i = 0; i < 5; i++)
{
     num = num * (5 – i);
     lblTest.Text += num + “ ”;

}

Write code that will reverse the digits of a number. For example, if num = 1234, then change num to 4321.

True or False?

!(x – y >= 1)

z <= 7 || y < 12

(x + y != 40) && (x != z)

(z – x >= y) || (y – x != z + 4)

(5 – x <= 2 * y) && (y – 15 >= z) || (x – 5 != y – 2 * z)

Explanation / Answer

1. True of False ----->

True or False

!(x – y >= 1)

True

z <= 7 || y < 12

False

(x + y != 40) && (x != z)

True

(z – x >= y) || (y – x != z + 4)

False

(5 – x <= 2 * y) && (y – 15 >= z) || (x – 5 != y – 2 * z)

True

2. Code ---->

int num = 1;
lblTest.Text = “”;
for (int i = 0; i < 5; i++)
{
     num = num * (5 – i);
     lblTest.Text += num + “ ”;

}

Output :-

10

3. Code ----->

int num = 1;
lblTest.Text = “”;
for (int i = 0; i < 5; i++)
{
     num = num * (5 – i);
     lblTest.Text += num + “ ”;

}

Output :-

15

ReverseNumber.cs ------->

    using System;       
    namespace ReverseNumber
    {
        class Program
        {
            static void Main(string[] args)
            {
                Console.WriteLine("Enter a No. to reverse");
                int Number = int.Parse(Console.ReadLine());
                int Reverse = 0;
                while(Number>0)
                {
                    int remainder = Number % 10;
                    Reverse = (Reverse * 10) + remainder;
                    Number = Number / 10;
                }
                Console.WriteLine("Reverse No. is {0}",Reverse);
                Console.ReadLine();
            }
        }
    }

Output :-

True or False

!(x – y >= 1)

True

z <= 7 || y < 12

False

(x + y != 40) && (x != z)

True

(z – x >= y) || (y – x != z + 4)

False

(5 – x <= 2 * y) && (y – 15 >= z) || (x – 5 != y – 2 * z)

True

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---