Consider a water tower like the one pictured at the introduction of this lab. Im

Question

Consider a water tower like the one pictured at the introduction of this lab.  Imagine a10-meter tall water tower develops a small hole at its base, 10 meters above the ground.  If the water tower is open to the atmosphere at the top and at the hole, how fast (speed, not time) would the water leak out of the hole?                                                                                                                                                   ____________________m/s

Consider a water tower like the one pictured at the introduction of this lab. Imagine a10-meter tall water tower develops a small hole at its base, 10 meters above the ground. If the water tower is open to the atmosphere at the top and at the hole, how fast (speed, not time) would the water leak out of the hole? Now, if the hole created a horizontal stream, how far from the base of the water tower would the water initially land?

Explanation / Answer

v=sqrt(2*g*h)

=sqrt(2*9.81*10)

=14 m/s

now time taken to land up

10=1/2*9.81*t^2

t=1.42 s

so Horizontal distance covered

Hx=14*1.42

=20 m ans

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