Please help I am stuck on problem two and I think its a matter of calculating n,
ID: 2256953 • Letter: P
Question
Please help I am stuck on problem two and I think its a matter of calculating n, which I seem to be getting wrong.
This is what my prof said but I am still getting the wrong answer some how.
"Ok, once again you're very close. For part 2,
q = (Tb-Tc)*(3/2)Rn
you're forgetting n, the number of moles you have. Without n, you're calculating the energy per mole. You can find n from the information at point A, since you know the temperature (300k), the volume (0.5L), and the pressure (2 atm).
Another way of approaching this is remembering that PV = nRT, so nR(Tb-Tc) = (PbVb - PcVc)
q = (3/2)(PbVb - PcVc)"
A heat engine has the three step cycle shown above. Starting from point A, 1 L (liter) of monatomic ideal gas expands in the isobaric (constant pressure) process A to B at P = 2 atm. B to C is isovolumetric process at V = 5 L, and C to A is an isothermal (constant temperature) compression at 300 K.
1) Find the pressure (in atm) at point C in atmospheres atm.
Pc = _____________ atm
Pa*Va=Pc*Vc
2*1=Pc*5
Pc = 0.4 atm = correct
2) Find the heat (in J) exhausted in the process B to C .
Q = __________________ J
q =(Tb-Tc)*(3/2)*Rn
I believe Tb is 1500K
Tc should v 300K
R=8.314
n=? This is what is screwing me up I think.
3) If the net work done by the engine per cycle is 482.9 J, find the work done by the gas during process C to A.
WCA = ________________ J
Wab = 2atm(5-1) = 8 atm-liter = 810.6 J
Wnet = Wab - Wac
Wac = 810.6 - 482.9 = 327.7 J = correct
q = (Tb-Tc)*(3/2)Rn you're forgetting n, the number of moles you have. Without n, you're calculating the energy per mole. You can find n from the information at point A, since you know the temperature (300k), the volume (0.5L), and the pressure (2 atm). Another way of approaching this is remembering that PV = nRT, so nR(Tb-Tc) = (PbVb - PcVc) q = (3/2)(PbVb - PcVc)" A heat engine has the three step cycle shown above. Starting from point A, 1 L (liter) of monatomic ideal gas expands in the isobaric (constant pressure) process A to B at P = 2 atm. B to C is isovolumetric process at V = 5 L, and C to A is an isothermal (constant temperature) compression at 300 K. Find the pressure (in atm) at point C in atmospheres atm. Pa*Va=Pc*Vc 2*1=Pc*5 Pc = 0.4 atm = correct Find the heat (in J) exhausted in the process B to C . q =(Tb-Tc)*(3/2)*Rn I believe Tb is 1500K Tc should v 300K R=8.314 n=? This is what is screwing me up I think. If the net work done by the engine per cycle is 482.9 J, find the work done by the gas during process Wab = 2atm(5-1) = 8 atm-liter = 810.6 J Wnet = Wab - Wac Wac = 810.6 - 482.9 = 327.7 J = correctExplanation / Answer
Applying ideal gas equation at point A,you will get n:
PV=nRT
=>n=PV/(RT)=2*1/(R*300)=1/(150R)
Now,
q =(Tb-Tc)*(3/2)*Rn
=>q=(1500-300)*(3/2)*R*(1/150R)=12J