In the figure below, a block slides down an incline. As it movesfrom point A to
ID: 2261310 • Letter: I
Question
In the figure below, a block slides down an incline. As it movesfrom point A to point B, which are 5.0 m apart, aforce F acts on the block, with magnitude1.4 N and directed down the incline.The magnitude of the frictional force acting on the block is 10 N.If the kinetic energy of the block increases by 40 J between A and B, how muchwork is done on the block by the gravitational force as the blockmoves from A to B?
Explanation / Answer
net work done = work done by external force + work done by gravitational force + workdone by friction
net work done = change in kinetic energy
40 J = WF + Wg + 10*5*cos(180)
40 J = 1.4*5 + Wg - 50 J
Wg =50+40-7= 83 J