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In the figure below, a block slides down an incline. As it movesfrom point A to

ID: 2261310 • Letter: I

Question

In the figure below, a block slides down an incline. As it movesfrom point A to point B, which are 5.0 m apart, aforce F acts on the block, with magnitude1.4 N and directed down the incline.The magnitude of the frictional force acting on the block is 10 N.If the kinetic energy of the block increases by 40 J between A and B, how muchwork is done on the block by the gravitational force as the blockmoves from A to B?

In the figure below, a block slides down an incline. As it moves from point A to point B, which are 5.0 m apart, a force F acts on the block, with magnitude1.4 N and directed down the incline. The magnitude of the frictional force acting on the block is 10 N. If the kinetic energy of the block increases by 40 J between A and B, how mu ch work is done on the block by the gravitational force as the block moves from A to B?

Explanation / Answer

net work done = work done by external force + work done by gravitational force + workdone by friction


net work done = change in kinetic energy

40 J = WF + Wg + 10*5*cos(180)

40 J = 1.4*5 + Wg - 50 J

Wg =50+40-7= 83 J