Please finish this question and if you can\'t do LT SPICE part. Its fine 5.0 Int
ID: 2266838 • Letter: P
Question
Please finish this question and if you can't do LT SPICE part. Its fine
5.0 Introduction An inductor time constant long enough to see with the multimeter time measuring system requires a very large inductor. A “made with wire, inductor of this value is impossible to make because it would be very, very big. There is a circuit called a simulated inductor (gyrator), which uses an op amp, two resistors and a capacitor to produce a branch relationship similar to an inductor. A simplified circuit for the simulated inductor, along with the equivalent circuit, is shown in Figure 5.0.1. Simulated inductors have some limitations. One terminal has to be at the ground, which limits the types of circuits that can be created. 5.0.1 Equations for RL Circuit =R..RG.CG R+Rs 1 e Fina To calculate L, RL 1.00 K, RG 100 K, C 330 uf. Rs 1.00 K.Explanation / Answer
5.1.1 Ans. Inductors have the exact opposite characteristics of capacitors. Capacitors store energy in an electric field, inductors store energy in a magnetic field. A fully discharged inductor, having no magnetic field, having zero current through it, will initially act as an open-circuit when attached to a source of voltage as it tries to maintain zero current, dropping maximum voltage across its leads.Current flow through the coil produces magnetic field around it. During the rise of current, we have changes in current which leads to changing magnetic field. This field gets induced from one winding of the coil to the other. This change in induced magnetic field will give rise to an opposing current that tries to nullify the current causing it. So, we can say the inductor opposes the change in current. Once the current reaches maximum and stabilises, there won't be any change in magnetic field. This means we will not have any opposing current. The change in current is zero. For an inductor L, voltage across it is given as V = L di/dt. Since di/dt is 0, V = 0. This is nothing but short circuit. Over time, the inductor’s current rises to the maximum value allowed by the circuit, and the terminal voltage decreases. At the exact instant power is applied, the capacitor has 0v of stored voltage and so consumes a theoretically infinite current limited by the series resistance, a short circuit. As time continues and the charge accumulates, the capacitors voltage rises and it's current consumption drops until the capacitor voltage and the applied voltage are equal and no current flows into the capacitor, an open circuit.
5.1.2 Ans. When it is connected to the ground for a long time, considering the fact that inductor is initially is not having any magnetic energy stored in it, therefore no voltage applied so current will be zero itself. And when the switch is changed from 0v to 5v, and as there is no energy in it, the current will also be zero initially.
5.1.3 Ans. when the switch is changed from 1 to 2, there is a change in voltage applied across the inductor, therefore the current flowing through the inductor slowly rises from 0 and reaches max I.e supported by the series resistor, at the steady state.
5.1.4 Ans. At t= infinity, inductor acts as short, therefore the total resistance seen the voltage source will be 2.00K ohms, and therefore the current will be 5/2.0k= 2.5mA