Can explain why impedance value of transmission line is 10 + j100 ohm? I can get
ID: 2266943 • Letter: C
Question
Can explain why impedance value of transmission line is 10 + j100 ohm? I can get it
2. Consider a system with the une lin diagram shown in 2. The 3 phase transformer name plate ratings are listed. The transformer reactances are given in percent, 10%-0.1 p.u. the transformer line and load impedance are in actual ohm. The generator terminal voltage magnitude) is 13.2 kV(line-to-line). Find the generator current, the transmissions current, the load current, the load voltage and the power delivered to the load. Vaa Zaced-300 ohm 13.2 kV x11-10% 13.24-132YkV 5 MVA 10 MVA 138Y -69kv = 896Explanation / Answer
here the impedance of the transmission line is given in actual form.i.e ohms.
consider for any transmission line it is a combination of resistance part and inductive reactance part.
so Z=R+jXL ohms.
if we convert this impedance in p.u,so
Zpu=Zactulal/Zbase.
where Z base=[base voltage]2/[base volt-ampere].
in general base volt-ampere is given or generator volt-ampere rating is taken as base volt-ampere.
in general generator voltage is taken as the base voltage from that we can calculate base voltage for the transformer secondary in KL transformer.so this is the base voltage for transmission line.