Please answer these two questions correctly with solution shown. ,11 58%. 12:49
ID: 2267725 • Letter: P
Question
Please answer these two questions correctly with solution shown.
,11 58%. 12:49 PM Assigned Join Codc: 719487 er Dissipation 4.9 Drivers #1 4.10 Drivers # Consider the output of one inverter "driving the input of another inverter. We can approximale Lhe propagalion delay asivc times the (Rx Ci time constant where R is the "on" resistance of the first inverter and C is the capacitance of the gates of the second nverler Typically we will use "minimum-sized inverters within circuits so the propagation dclay of one minimum sized invcrler driving another minimum-sized would be 5 x IRminx Cmin. Now conside minimum-sized inverter is driving an Answered r the siluation where aExplanation / Answer
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If rmin * Cmin = Tau, then the delay without loading = 5*Tau. For the first case, as shown in the question, delay = 500*Tau, which means the delay has increase by a factor of 100. For the tird case, delay = 5*10*100*Tau = 5000*Tau. In comparison to 500*Tau, the delay has now increased by a factor of 10.
For the second part, if the propagation delay for each inverter is Tau, and n inverters are used, total propagation delay = (Tau)^(n-1). If desired delay = d, then, (Tau)^(n-1) = d or n = (log(d)/log(Tau)) + 1. Plug in the value of d (not given) and find the answer.