Please help me solve these. 1, 2 and 3 are connected and so are 4 and 5. - 1300

Question

Please help me solve these. 1, 2 and 3 are connected and so are 4 and 5.

- 1300 F capacitor is con- nected in series with a 50 k2 re- sistor to a 64 V voltage source At t-0, the charge on the capac- itor is zero. 1AO The current is constant ver time. BO After a long time, Vc will be almost zero, while VR will be almost 64 V. While the voltage Vc across the capacitor changes, the voltage VR across the resistor remains constant. DQ The current through the circuit decreases over time. Initially, VR is almost zero, while Vc is almost 64 V. FO As the charge on the capacitor increases over time, so does the current through the circuit. 1.2 pt At what time is the charge on the capacitor 10400 C? (in s) DO 9 EO 26 FO 38 1.2 pt At what time is the voltage Ve across the capacitor 32 V? (in s) DO 26 EO 38 FO 45

Explanation / Answer

1.

The Current through the circuit decreases over time .

2.

In a RC circuit charge as a function of time for charging is given by

Q=Qmax(1-e-t/T)

Time Constant

T=RC=50*103*1300*10-6=65 s

maximum charge

Qmax =64*1300 =83200 uC

=>10400 =83200 (1-e-t/65)

Ln(0.875) =-t/65

t=8.68 s =9 s

3.

Voltage acorss capacitor as a function of time is given by

V=Vmax(1-e-t/T)

32=64(1-e-t/65)

Ln(0.5) =-t/65

t=45 s

4.

Intially VR is almost zero ,while VC is almost 64 V

5.

In a RC circuit Voltage as a function of time for discharging is

V=Vmaxe-t/T

32=64e-t/65

Ln(0.5)=-t/65

t=45 s

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