The next two parts deal with the potential away from the straight line joining t

Question

The next two parts deal with the potential away from the straight line joining the two electrodes. We will be looking for points that have the same potential as (4,4) cm, i.e., we want to map the equipotential line.

The next two parts deal with the potential away from the straight line joining the two electrodes. We will be looking for points that have the same potential as (4,4) cm, i.e., we want to map the equipotential line. Where along the y = 6 cm is the potential the same as (4,4) cm? Click on the graph, then click on the "Submit Answer" button.

Explanation / Answer

the potential is given by

V = k x (q/r)

where k = (1/4pi x e_o) = 9 x 10^9 Nm^2/C^2,q is the charge and r is the distance

here,r = [(4 - 0)^2 + (6 - 4)^2]^1/2 x 10^-2 m

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