An electric field given by E = 8.67i - 6.93( y 2 + 5.43)j pierces the Gaussian c
ID: 2271511 • Letter: A
Question
An electric field given by E= 8.67i - 6.93(y2 + 5.43)j
pierces the Gaussian cube of the figure, where the cube is 0.590 m on a side. (E is in newtons per coulomb and y is in meters.) What is the electric flux through the (a) top face, (b) bottom face, (c) left face, and (d) back face? (e) What is the net electric flux through the cube?
An electric field given by E= 8.67i - 6.93(y2 + 5.43)j pierces the Gaussian cube of the figure, where the cube is 0.590 m on a side. (E is in newtons per coulomb and y is in meters.) What is the electric flux through the (a) top face, (b) bottom face, (c) left face, and (d) back face? (e) What is the net electric flux through the cube?Explanation / Answer
at top of phase flux = E*A = 0.59^2*-6.92*(0.59^2 + 5.43)=-13.92
at bottom E = -0.59^2*-6.93*(0^2+5.43)=13.1
left face = 8.67*-0.59^2=-3.02
right phase = 867*0.59^2 = 3.02
nextflux = -13.92 + 13.1-3.02+3.02=-0.82