I will give the best answer to the person that explains this step by step with t

Question

I will give the best answer to the person that explains this step by step with the correct answers.

You would Ike to shoot an orange out of a tree with your bow and arrow The orange is hanging 5.00 m above the ground. On your first try. you fire the arrow at 37 0 m/s at an angle of 30.0* above the horizontal from a height of 1.30 m white standing 54 0 m away Treating the arrow as a point projectile and neglecting air resistance. what is the height of the arrow once it has travelled the 54 0 m horizontally to the tree? if you fire at the same speed and angle on your second try. how far away could you stand such that the arrow w4 hit the orange? Select all that apply.

Explanation / Answer

Vx = 37*cos30 = 32.04 m/s y2-y1 = x*tan30 - 0.5*g*x^2/Vx^2 y2 - 1.3 = 54*tan30 - 4.9*54^2/32.04^2 y2 = 18.5582 m b) y2 = 5m 5 - 1.3 = x*tan30 - 4.9*x^2/32.04^2 3.7 = 0.5774 - 0.0048x^2 0.0048x^2 - 0.5774+3.7 = 0 x = 113.50 m

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