A. Precipitation of CaC,O HO from the Salt Mixture Trial 2 Trial 1 Unknown numbe

ID: 227684 • Letter: A

Question

A. Precipitation of CaC,O HO from the Salt Mixture Trial 2 Trial 1 Unknown number- 00.2517 100.24QD I. Mass of beaker () 2. Mass of beaker and salt mixture(g) 3. Mass of salt mixture (g) 4. Mass of filter paper (g) 5. Mass of filter paper and product after air-dried 0132 33 1.1113 LU 110745 9945943 30 13990 0.4047 or oven-dried (g) 0:40 6. Mass of dried product (g) 7. Formula of dried product B. Determination of Limiting Reactant I. Limiting reactant in salt mixture (write complete formula) 2. Excess reactant in salt mixture (write complete formula) Data Analysis 1. Moles of CaC,o,tH,O (or CaCO) precipitated (mob 01002752 al-0:0077152 Mo 2. Moles of limiting reactant in salt mixture (mol . formula of limiting hydrate 3. Mass of limiting reactant in salt mixture (g) 4. Mass of excess reactant in salt mixture (g) . formula of excess hydrate 5. Percent limiting reactant in salt mixture (%) 6. Percent excess reactant in salt mixture (%) 7. Mass of excess reactant that reacted (g) 8. Mass of excess reactant, unreacted (g) Show calculations for Trial 1 on next page. Experiment 8 13

Explanation / Answer

Since masses of limiting reactant (LR) and excess reactant (ER) are not given,

Let the mass of limiting reactant (K2C2O4.H2O) added for trial 1 & trial 2 = L1 and L2 grams

And mass of excess reactant (CaCl2.2H2O) added for trial 1 & trial 2 = E1 and E2 grams

Molar mass of LR = 184.23 g/mol

Molar mass of ER = 147 g/mol

Apply below equations for answers:

Trial 1

Trial 2

Mass of dried product, g

0.4047

Formula of dried product

CaC2O4.H2O

Moles of CaC2O4.2H2O precipitated

0.002752

Moles of LR in salt mixture, mol

L1/184.23

L2/184.23

Mass of LR in salt mixture, g

% LR in salt mixture

L1/(L1+E1) * 100

L2/(L2+E2) * 100

% ER in salt mixture

E1/(L1+E1) * 100

E2/(L2+E2) * 100

Mass of ER that reacted, g

L1*147/184.23

L2*147/184.23

Mass of ER unreacted, g

E1-(L1*147/184.23)

E2-(L2*147/184.23)