Problem 18.21 Suppose 105 moles of a monatomic ideal gas undergo an isothermal e

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Problem 18.21 Suppose 105 moles of a monatomic ideal gas undergo an isothermal expansion from 1.00 m3 to 4.00 m3, as shown in the figure(Figure 1) . Problem 18.21 Suppose 105 moles of a monatomic ideal gas undergo an isothermal expansion from 1.00 m3 to 4.00 m3, as shown in the figure(Figure 1) . Suppose 105 moles of a monatomic ideal gas undergo an isothermal expansion from 1.00 m3 to 4.00 m3, as shown in the figure(Figure 1) . Suppose 105 moles of a monatomic ideal gas undergo an isothermal expansion from 1.00 m3 to 4.00 m3, as shown in the figure(Figure 1) . Part A What is the temperature at the beginning of this process? Ti =
K SubmitMy AnswersGive Up Part B What is the temperature at the end of this process? Tf =
K SubmitMy AnswersGive Up Part C How much work is done by the gas during this expansion? W =
kJ SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining Provide Feedback Part A What is the temperature at the beginning of this process? Ti =
K SubmitMy AnswersGive Up Part B What is the temperature at the end of this process? Tf =
K SubmitMy AnswersGive Up Part C How much work is done by the gas during this expansion? W =
kJ SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining Part A What is the temperature at the beginning of this process? Ti =
K SubmitMy AnswersGive Up Part B What is the temperature at the end of this process? Tf =
K SubmitMy AnswersGive Up Part C How much work is done by the gas during this expansion? W =
kJ SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining Part A What is the temperature at the beginning of this process? Ti =
K SubmitMy AnswersGive Up Part B What is the temperature at the end of this process? Tf =
K SubmitMy AnswersGive Up Part C How much work is done by the gas during this expansion? W =
kJ SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining Part A What is the temperature at the beginning of this process? Ti =
K SubmitMy AnswersGive Up Part A What is the temperature at the beginning of this process? Ti =
K SubmitMy AnswersGive Up Ti =
K Ti =
K SubmitMy AnswersGive Up Part B What is the temperature at the end of this process? Tf =
K SubmitMy AnswersGive Up Part B What is the temperature at the end of this process? Tf =
K SubmitMy AnswersGive Up Tf =
K Tf =
K SubmitMy AnswersGive Up Part C How much work is done by the gas during this expansion? W =
kJ SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining Part C How much work is done by the gas during this expansion? W =
kJ SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining W =
kJ W =
kJ SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining Incorrect; Try Again; 5 attempts remaining Incorrect; Try Again; 5 attempts remaining Provide Feedback of 1 Problem 18.21 Suppose 105 moles of a monatomic ideal gas undergo an isothermal expansion from 1.00 m3 to 4.00 m3, as shown in the figure(Figure 1) . Part A What is the temperature at the beginning of this process? Ti =
K SubmitMy AnswersGive Up Part B What is the temperature at the end of this process? Tf =
K SubmitMy AnswersGive Up Part C How much work is done by the gas during this expansion? W =
kJ SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining Provide Feedback of 1 Suppose 105 moles of a monatomic ideal gas undergo an isothermal expansion from 1.00 m3 to 4.00 m3, as shown in the figure(Figure 1) . What is the temperature at the beginning of this process? What is the temperature at the end of this process? How much work is done by the gas during this expansion?

Explanation / Answer

1.) T = PV/nR =400000*1/105*8.314 = 458 K

2.) Tf = Ti = 458 K since the reaction is isothermal.

3.)W = -nRTln(Vf/Vi) = 105*8.314*458ln4 = 554.27 kJ

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