A parallel plate capacitor with adjustible plate separation d and adjustible are
ID: 2279415 • Letter: A
Question
A parallel plate capacitor with adjustible plate separation d and adjustible area A is connected to a battery. The capacitor is fully charged to Q Coulombs and a voltage of V Volts. (C is the capacitance and U is the stored energy.) Give all correct answers concerning a parallel-plate capacitor charged by a battery (e.g. B, AC, CDF).
A) After being disconnected from the battery, increasing the area A will decrease V.
B) With the capacitor connected to the battery, increasing the area A will increase U.
C) With the capacitor connected to the battery, decreasing d increases U.
D) With the capacitor connected to the battery, decreasing d decreases Q.
E) With the capacitor connected to the battery, increasing d increases C.
F) After being disconnected from the battery, increasing the area A will increase C.
An explanation with your answer would be amazing. I have looked at a ton of these online and still can't get the correct solution to my specific problem so IDK waht is going wrong. Thanks!!!!
Explanation / Answer
Q=CV=C1V1
V1=CV/C1
C1=?0A/d
a) A increase C1 increase
V1 decrease . right
b) U=(1/2)*C1*V^2
A increase C1 increase
U increase right
c) d decrease C1 increase
U increase right
d) d decrease C1 increase
Q=C1V
Q increases
e) d increase C1 decreases
f) A increase C1 will increase.