Description: Exercise 23.60 Three charges, q 1 , q 2 , and q 3 , are located at
ID: 2281220 • Letter: D
Question
Description: Exercise 23.60
Three charges, q1, q2, and q3, are located at the corners of an equilateral triangle with side length of 1.29m.
a) Find the work done to bring the first particle, q1=1.83pC, to P from infinity,
Please include a multiplication sign (*) to indicate that two units are being multiplied.
W1=[Num] [Units]
b) Find the work done to bring the second particle, q2=2.01pC, to Q from infinity,
Please include a multiplication sign (*) to indicate that two units are being multiplied.
W2=[Num] [Units]
c) Find the work done to bring the last particle, q3=3.55pC, to R from infinity.
Please include a multiplication sign (*) to indicate that two units are being multiplied.
W3=[Num] [Units]
d) Find the total potential energy stored in the final configuration of q1, q2, and q3.
Please include a multiplication sign (*) to indicate that two units are being multiplied.
Utot=[Num] [Units]
Three charges, q1, q2, and q3, are located at the corners of an equilateral triangle with side length of 1.29m.
a) Find the work done to bring the first particle, q1=1.83pC, to P from infinity,
Please include a multiplication sign (*) to indicate that two units are being multiplied.
W1=[Num] [Units]
b) Find the work done to bring the second particle, q2=2.01pC, to Q from infinity,
Please include a multiplication sign (*) to indicate that two units are being multiplied.
W2=[Num] [Units]
c) Find the work done to bring the last particle, q3=3.55pC, to R from infinity.
Please include a multiplication sign (*) to indicate that two units are being multiplied.
W3=[Num] [Units]
d) Find the total potential energy stored in the final configuration of q1, q2, and q3.
Please include a multiplication sign (*) to indicate that two units are being multiplied.
Utot=[Num] [Units]
Explanation / Answer
a) W1 = work done to bring the charge particle q1 = 0 j
b)W2 =work done to bring the charge particle q2
= k*q2*q1/1.29
= 9*10^9 *(1.83*2.01 * 10^-12 * 10^-12 )/1.29
=25.66*10^-15 J
C) W3 = work done to bring the charge particle q3
= k*q3*q1/1.29 + k*q2*q3/1.29
= kq3(q1+q2)/1.29
= 9*10^9 *3.55(1.83+2.01 )*10^-24/1.29
=95.10 *10^-15 J
d) U = potential energy
= W1 +W2 +W3
= 25.66*10^-15 J + 95.10 *10^-15 J
=120.76 *10^-15 j