Please show step by step procedure on how to solve this problem. I have been str

Question

Please show step by step procedure on how to solve this problem. I have been struggling with this problem for over an hour and don't understand how to solve it. Any help would be greatly appreciated. Thanks!!

In a physics lab experiment for the determination of moment of inertia, a team weighs an object and finds a mass of 4.34 kg. They then hang the object on a pivot located 0.189 m from the object's center of mass and set it swining at a small amplitude. As two of the team members carefully count 123 cycles of oscillation, the third member measures a duration of 241 s. What is the moment of inertia of the object with respect to its center of mass about an axis parallel to the pivot axis?

__________ kg * m2

Explanation / Answer

T = 2pi * sqrt(I / m g d)

I = Icm + m d^2

241/123 = 2*pi*sqrt( (I + 4.34*0.189^2)/(4.34*9.81*0.189))

1.95935 = 2*pi*sqrt( (I + 0.15503) / (8.047))

0.312 = sqrt( (I + 0.15503) / (8.047))

0.09724 = (I + 0.15503) / (8.047)

I = 0.6275 kgm^2

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