Mast Chapter 10 Homework-Internet Explorer chemistry.com/myct/t roblem D offsetn

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Mast Chapter 10 Homework-Internet Explorer chemistry.com/myct/t roblem D offsetnnet Chapter 10 Homework Problem 10.42- Enhanced-with Feedback Constants 1 Perlodic Table You may want to reference (Pages 340 346) Section 10.6 while completing this problem. Compiete the following table for solutions at 20°C Part A Solution! |[OH-1 Acidic, basic, or neutral? [HsOtl pH (M(M Part A Part B 11.75 Part Part D Part E Part F Neutral if the pH of Solution 1 is 11.75, what is |H,0' Express your answer to two significant figures 13.8 × 10 121 Part G | Part H | Part [H30+ ] = Submt Request Answer Part B It the plI of Solution 1 is 11.75, what is (OH 1? Express your answer to two signiticant figures

Explanation / Answer

slution     [H3O^+] in M             [OH^-] in M           PH            Acidic, basic or neutral
1           1.78*10^-12               5.6*10-3           11.75            basic
2            1*10^-7                    1*10^-7            7                   neutral
3           3.8*10^-12               2.6*10^-3           11.42            basic

part-A solution 1
PH   = 11.75
-log[H3O^+] = 11.75
    [H3O^+]   = 10^-11.75
              = 1.78*10^-12M
part-B
PH   = 11.75
-log[H3O^+] = 11.75
    [H3O^+]   = 10^-11.75
              = 1.78*10^-12M
[OH^-] = Kw/[H3O^+]
        = 1*10^-14/1.78*10^-12
        = 0.0056M = 5.6*10-3M
part-C
basic
solution 2
part-D
[H3O^+] = 10^-7 M
part-E
[OH^-]   = 10^-7 M
part-F
PH = 7
solution -3
part-G
[H3O^+]   = 3.8*10^-12M
[OH^-]    = Kw/[H3O^+]
          = 1*10^-14/3.8*10^-12
          = 2.6*10^-3M
part-H
[H3O^+]   = 3.8*10^-12M
PH = -log[H3O^+]
     = -log3.8*10^-12
     = 11.42
part-I
basic

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