Imagine a proton that is launched with an initial speed V init (V init >0) from
ID: 2288098 • Letter: I
Question
Imagine a proton that is launched with an initial speed Vinit (Vinit>0) from a 12V equipotential line. Suppose that the proton later crossed a 16V equipotential line.
1. Would the proton gain or lose electric potential energy moving from the 12V equipotential line to the 16V equipotential line? EXPLAIN please!
2. Determine the change in electric potential energy of the proton during this portion of its motion. (Note/hint: 1C*1V=1J - what is the charge of a proton in coulombs?)
3. At the moment when the proton crosses the 16V equipotential line, would its speed be greater than, less than, or equal to its initial launch speed Vinit? EXPLAIN please! (Hint: Use conservation of energy!)
Suppose that, after being launched with speed Vinit from the 12V equipotential line and crossing the 16V equipotential line, the proton were to return to the original 12V equipotential line.
4. At the moment when the proton returns the 12V equipotential line, would its speed be greater than, less than, or equal to its inital launch speed Vinit? EXPLAIN please! Thank you!!
Explanation / Answer
1. As proton moves from higher potential line its potential energy wil increase.
explanation for moving ower potential to higher potential the extra energy is required which will store in form of potential energy
2 .Change in potential energy = Vq = (16-12)x 1.6 x 10^-19=6.4x 10^-19 j
3. when the proton reaches 16V line its velocity is decrease because potential energy increase is comes from loss of kinetic enegy
4. when it again comes to 12 v the velocity will be same to the earlier velocity.