Three resistors, 2.2 ?, 4.2 ?, and 5.4 ?, and a battery whose emf is 24 V are co

Question

Three resistors, 2.2 ?, 4.2 ?, and 5.4 ?, and a battery whose emf is 24 V are connected in series.

1) What is the potential difference across each of these four elements?

2) What fraction of the total power is dissipated in each of the resistors?

a) power dissipated by 2.2 ? resistor / total power = __________

b) power dissipated by 4.2 ? resistor / total power = __________

c) power dissipated by 5.4 ? resistor / total power = __________

a) 2.2 ? resistor     __________V b) 4.2 ? resistor     __________V c) 5.4 ? resistor     __________V d) 24 V battery __________V

Explanation / Answer

(a)

total current(I)=Vb/R=24/(2.2+4.2+5.4)=2.034A

V(2.2)=Ix2.2=2.034x2.2=4.47V

V(4.2)=Ix2.2=2.034x4.2=8.54V

V(5.4)=Ix2.2=2.034x5.4=10.98V

(b)

P=VI

P(2.2)=IxV(2.2)=2.034x4.47=9.092W

P(4.2)=IxV(4.2)=2.034x8.54=17.37W

P(5.4)=IxV(5.4)=2.034x10.98=22.34W

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