Please help with the 3 highlighted pieces within the image. 1. I\'m not sure how

Question

Please help with the 3 highlighted pieces within the image.

1. I'm not sure how the -A translates into the table ~ does it go into the Xi space or the Yi space of the truth table? Then how does it become the C0? It's the only one I couldn't figure out :(

2. Then, how does the truth table translate into the multiplexer?

3. How does the initial carry c0 get expressed as a function?

.

1. Sequence assignment Arithmetic Function A- 1 Op2Op 0 1 2. Processor Design able Lu Op2 Opi Co ail 0 1 1 0 ai bi bi ai Label the data inputs of the two 4-to-1 multiplexers given below for the realization of xi, yi. GA 153 A2 A1 B3 B2 B1 B0 GB s1 S0 Op2 Op1 Express the initial carry co as a function of Op2 and Op1.

Explanation / Answer

For the first part

Assume this as a full adder circuit for your understanding.

1) For (Op2,Op1) as (0,1) => xi = 0, yi = ai , co = 1

Note: It seems that part c where (Op2,Op1) is (1,0) , co should be 0 instead of 1

2)For part 2

From the truth table we can see that and IC153 says that 00 corresponds to A0/B0, 01 to A1/B1, 10 to A2/B2 and 11 to A3/B3 and hence

A0 = ai ,A1 = 0, A2 = ai, A3 = bi

B0 = 1,B1 = ai, B2 = bi, B3 = ai

3) co as a function of op2 and op1 is co = op1 (Assuming part c answer is wrong (as it has to be wrong else there is no way of solving this question))

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