Question
Please show your work. I can understand how.
In a truck-loading station at a post office, a small 0.200 - kg package is released from rest at point A on a track that is one-quarter of a circle with radius 1.60 m (the figure (Figure 1)). The size of the package is much less than 1.60 m, so the package can be treated as a particle. It slides down the track and reaches point B with a speed of 4.60m/s . From point B, it slides on a level surface a distance of 3.00 m to point C, where it comes to rest. What is the coefficient of kinetic friction on the horizontal surface? How much work is done on the package by friction as it slides down the circular are from A to B
Explanation / Answer
coefficient of kinetic friction =.425
work = -.636J (idk why)