Instead of using HCl to standardize NaOH a student used potassium hydrogen phtha

Question

Instead of using HCl to standardize NaOH a student used potassium hydrogen phthalate. KHC8H4O4 which has a molar mass of 204 g/mole. It required 32.46 mL of NaOH to titrate 1.45g of KHC8H4O4 to a pale pink endpoint, what is the molarity of NaOH? KHC8H4O4 + NaOH —> K+ + Na+ + C8H4O4 2- + H2O Instead of using HCl to standardize NaOH a student used potassium hydrogen phthalate. KHC8H4O4 which has a molar mass of 204 g/mole. It required 32.46 mL of NaOH to titrate 1.45g of KHC8H4O4 to a pale pink endpoint, what is the molarity of NaOH? KHC8H4O4 + NaOH —> K+ + Na+ + C8H4O4 2- + H2O

Explanation / Answer

A:- Balanced chemicall equation,

KHC8H4O4 + NaOH —> K+ + Na+ + C8H4O42- + H2O

1 mole            1 mole

moles of KHC8H4O4 = (1.45 g / 204 g/mole)

                               = 0.0071078 moles

At equilaence point, number of moles of KHC8H4O4 = number of moles of NaOH

so number moles of NaOH = 0.0071078 moles

molarity of NaOH, M = 0.0071078 mole / 0.03246 L

                              = 0.219 M

The molarity of NaOH = 0.219 M

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---