Parts (a) and (b) (9%) Problem 11 : A 2.8-cm-tall object is placed 4.8 cm in fro

Question

Parts (a) and (b)

(9%) Problem 11 : A 2.8-cm-tall object is placed 4.8 cm in front of a convex mirror with radius of curvature 25 cm. 33% Part (a) What is the image distance, in centimeters? Include its sign. s, 5.88 sin0 7 8 9 HOE cos0 cotan0 asin acosO atanacotan sinh(0 cosh0anh0cotanh0 O Degrees O Radians END BACKSPACE | DELI CLEAR Submit Hint I give up! Hints: 290 deduction per hint. Hints remaining: 2 Feedback: 2% deduction per feedback. 33% Part (b) What is the image height, in centimeters? Include its sign.

Explanation / Answer

for convex mirror,

f = - R/2 = - 12.5 cm

object distance, p = 4.8 cm

Applying 1/f = 1/p + 1/q

1/(-12.5) = 1/4.8 + 1/q

q = - 3.5 cm

(A) - 3.5

(B) m = - q / p = hi / ho

- (-3.5)/(4.8) = hi / 2.8

hi = 2.02 cm

Ans: 2.02

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