Say you have a monatomic substance simulated with 100 atoms on the computer simu
ID: 2307070 • Letter: S
Question
Say you have a monatomic substance simulated with 100 atoms on the computer simulation program Atoms-ln-Motion. You see that it is in its solid phase and when all KE is removed and the temperature reads 0 K, the PE of these 100 atoms is -400 Times 10^-21 J. You therefore know that the bond energy of these 100 atoms is -400 Times 10^-21 J. The well depth, e, for these atoms is 0.8 Times 10^-21 J. Determine the average number of nearest-neighbors for each atom (refer to Activity 3.2.3 "Connecting the Particle Model of Bond Energy to Macroscopic Empirical Values" Why do you think that the average number of nearest-neighbors per atom turns out to be less than 12 for this sample of 100 atoms?Explanation / Answer
the average number of nearest-neighbors for each atom:
n = E/(A.e)
Here, e=0.8x10-21 J
E =400x10-21 J
A= 100
Thus, n =5
This is less than12 suggests the 100 atoms
Because they are same type
and are arranged in a simple cubic unit.