In a Three-phase circuit with a star generator and charge, we have the following
ID: 2313408 • Letter: I
Question
In a Three-phase circuit with a star generator and charge, we have the following canceled voltages in a positive sequence: Van = 110, (Vbn and Vcn are determined with the data presented).
The Charge of ZA = 22Ohms
The Impedance of line Zla is worthless
The Impedance of generator Zga is worthless
The Neutral Impedance Z0 is worthless
All Impedances are balanced
***Picture of the Circuit is attached.***
Find the currents for the Three-phase line: laA, lbB and lcC:
a) laA = 5
lbB = 5e^120j
lcC = 5e^-120j
b) laA = 5e^-120j
lbB = 5e^120j
lcC = 5e^0j
c) laA = 5
lbB = 5e^-120j
lcC = 5e^120j
d) laA = 5e^120j
lbB = 5e^-120j
lcC = 5e^0j
Explanation / Answer
line current magnitude =110/22=5
and these are in same direction as positive sequence so option c is correct one