Could anyone give a detailed solution to this question, including a comprehensib

Question

Could anyone give a detailed solution to this question, including a comprehensible explanation?

th you connect Tour iau kur capacitors so tne ner capacitance is 1.0 pF? 28. Two capacitors, of 2.0 and 6.0 uF, respectively are initially charged to 24 connecting each, for a few instants, to a 24-V battery. The battery is then removed and the charged capacitors are connected in a closed series drcuit, the positive terminal of each capacitor being connected to the negative terminal of the other (Fig. 26.31). What is the final charge on each capacitor? What is the final potential difference FIGURE 26-31 Tor capaciosers cannected in series after they have been chanted 29. Three capacitors of capacitance 20AEG

Explanation / Answer

The initial charges on the capacitors before they are connected in the curcuit:

Q = CV

Q2 = (2 X 10-6)(24) = 4.8 X 10-5 C   or 48 C

Q6 = (6 X 10-6)(24) = 1.44 X 10-4 C or 144 C

Then we connect them in series with positive to negative for each capacitor.

144 C - 48 C = 96 C that is the total charge on each capacitor.

To find the potential difference, Q = CV so V = Q/C

V2 = (96 X 10-6)/(2 X 10-6) = 48V

V6 = (96 X 10-6)/(6 X 10-6) = 16V

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