I performed an experiment using a pulley system with two masses m1 and m2. The m

Question

I performed an experiment using a pulley system with two masses m1 and m2. The mass of m1=40.13 g, the mass of m2=119.34. The mass difference (m1-m2) is 20.79g. I am asked to use the average time (t=1.83s) and the travelled distance (h=102.3cm) to calculate the acceleration of the system for each mass difference.

Note that since the system is released from rest, we can write h=y-y0=1/2at^2?

We know;

h=102.3

t=1.83

y=20.79

I dont know how to solve for the acceleration a, without knowing the value of y0?

Explanation / Answer

we dont need the value of Yo here

we simply use

h = (0.5) a t2

102.3 = (0.5) a (1.83)2

a = 61.1 m/s2

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