For simplicity, we will assume that golden manes (G) are dominant over black man
ID: 252587 • Letter: F
Question
For simplicity, we will assume that golden manes (G) are dominant over black manes (g), and thick manes (T) are dominant over thin (t).(In reality, the inheritance of these traits is a lot more complex and lions exhibit a range of mane colours from golden to brown to dark brown to black – but here we will keep it simple.)
Phenotype
Number of lions
Locus 1: Mane Colour
Golden
821
Black
211
Locus 2: Mane Density
Thick
354
Thin
678
(i) The frequency of black manes: 0.204
(ii) The frequency of golden manes: 0.795
(i) The frequency of thick manes: 0.343
(ii) The frequency of thin manes: 0.656
Assuming the African population is in Hardy-Weinberg equilibrium for the two loci, what are the observed frequencies of each allele (G, g, T and t) in this lion population?
Round your answer to three decimal places and submit your answer in the correct format (e.g. 0.062).
(a) Frequency of the G allele = ---------------------------
(b) Frequency of the g allele = ----------------------------
(c) Frequency of the T allele =----------------------------
(d) Frequency of the t allele = ----------------------
Phenotype
Number of lions
Locus 1: Mane Colour
Golden
821
Black
211
Locus 2: Mane Density
Thick
354
Thin
678
Explanation / Answer
Answer:
(a) Frequency of the G allele =0.548
(b) Frequency of the g allele = 0.452
(c) Frequency of the T allele =0.190
(d) Frequency of the t allele = 0.810
Explantion:
1).
Frequency of black manes (gg)= 0.204
Frequency of black mane allele (g) = SQRT of 0.204 = 0.452
As p+q=1
p= 1-q=1-0.452= 0.548
The frequency of golden mane allele (G)= 0.548
2).
Frequency of thin manes (tt)= 0.656
Frequency of thin mane allele (t) = SQRT of 0.656 = 0.810
As p+q=1
p= 1-q=1-0.810= 0.190
The frequency of thick mane allele (T)= 0.190