Show all work and explain key steps A protein, shown schematically in the right

Question

Show all work and explain key steps

A protein, shown schematically in the right figure, may contain several cysteines (represented as labeled light gray balls), which may pair together to form disulfide bonds. For six cysteines, three disulfide bonds can form; the figure shows the pairing arrangement 1–6, 2–5, 3–4. How many different disulfide pairing arrangements are possible? Derive the general formula for the entropy of forming different disulfide bonds when there are n cysteines (and n is even). Answer without explanation will not get any point. (10 points) Apodoba

Explanation / Answer

Answer:

Since there are Six Cysteines and a disulphide bond is formed between two cysteine residues.

So for Six cysteines ,

The possible number of disulphide bond arrangement is (n-1)+ (n-2) + (n-3) + (n-4) + (n-5) where n is the number of cysteines residue.

So for 6 cysteines.

possible Number of disulphide bond arrangement is

i.e = 5 +4+3+2+1 = 15

So a general formulae can be summation of ( N-n) terms, where N = number of cysteines and

n= 1 to N-1.

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---