Part A. (5 points) In the pea plants that Mendel studied, purple/violet flowers
ID: 274612 • Letter: P
Question
Part A. (5 points) In the pea plants that Mendel studied, purple/violet flowers are dominant to white flowers and ye are W for purple/iolet flowers, wfor white flowers, G for yellow peas, and g for green peas 1) You are provided two plants with the genotypes Ggww and ggWW. Indicate their corresponding phenotype.(1 point 2) Now you must cross these plants together to yield an F1 generation, Write out the expected gametes for each parent.2 points) Ggww gametes ggWW gametes- You will use Mendel's final two laws to generate their gametes. State the two laws and define them in the context of these parents. Name of the Law and a one complete sentence description required. 2 points Law 1 (name and description) Law 2 (name and description)Explanation / Answer
1. GgWw = Yellow peas and purple flowers
ggWW = Green peas and purple flowers
2. Parental cross: GgWw X ggWW
Gametes produced by GgWw = (GW) (Gw) (gW) (gw)
Gametes produced by ggWW = (gW)
3. 1. Mendel is considered as the father of genetics. He proposed to principles based on his observations on pea plants.
i. Law of segregation: Alleles of a gene segregate independently of each other during gametogenesis.
Mendel crossed a tall pea plant with a short plant (Both pure lines) and observed tall plants in the F1 progeny. When F1 plants are selfed, he could find tall and short plants in the ratio of 3:1.
Parental cross: TT X tt
F1 progeny: Tt
F1 selfing: Tt X Tt
F2 progeny: TT Tt Tt tt
Genotypic ratio = 1:2:1
Phenotypic ratio = 3:1
ii. Law of independent assortment: Alleles of two different genes assort independently of each other.
Mendel crossed pea plants with round seeds and yellow flowers (RRYY) with plants having constricted seeds and green flowers (rryy). All the F1 progeny are round and yellow (RrYy). However, four different progeny are obtained in the F1.
Round yellow = 9
Round green = 3
Constricted yellow = 3
Constricted green = 1
Genotypic ratio = 1:1:1:1:2:2:2:2:4
Phenotypic ratio = 9:3:3:1