Please do not copy answer from another similiar Q from Chegg these numbers are d

Question

Please do not copy answer from another similiar Q from Chegg these numbers are different :)

The Chamber of Commerce periodically sponsors public service seminars and programs. Currently, promotional plans are under way for this year's program. Advertising alternatives include television, radio, and newspaper. Audience estimates, costs, and maximum media usage limitations are as shown:

To ensure a balanced use of advertising media, radio advertisements must not exceed 50% of the total number of advertisements authorized. In addition, television should account for at least 10% of the total number of advertisements authorized.

Constraint Television Radio Newspaper Audience per advertisement 110,000   18,000   30,000   Cost per advertisement $1,500   $250   $500   Maximum media usage 11   21   13  

Explanation / Answer

Let

T = Number of television spots

R = Number of Radio spots

N = Number of newspaper ads

Max = 110,000T + 18,000R + 30,000N

such that 1500T + 250R + 500N < 23000

Constraints -

T < 11

R < 21

N < 13

-0.5T + 0.5R - 0.5N 0

0.9T - 0.1R - 0.1N 0

T, R, N, 0

using solver,

T = 3.25, R = 16.25 and N = 13

which can be rounded to T = 3, R = 16, N = 13

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