Conducting your own Chi-square 4 different kinds of beans have been mixed and pl
ID: 279523 • Letter: C
Question
Conducting your own Chi-square 4 different kinds of beans have been mixed and placed into a large container. The beans should all exist in equal amounts or a ratio of 1:1:1:1. Remove a random sample of the bean mixture. Separate and count each bean type. Fill in the table below Calculation of ?2 for a sample removed from a population Type of Observed Expected (O-E)(O-E)(O-E)/E Bean 0.06 Totals 311 D63 2.2 1) What is our null hypothesis (in terms of bean sampling) for this test? 2) What is our alternative hypothesis? 3) How many degrees of freedom are there? hat probability does your x value correspond to? P 0. 004 0 63 5) s this value significant or not significant (according to the x table)? 6) Which hypothesis is supported by the results of your X test? 7) Please write your interpretation of the results of this experiment (what do your results tell you about your sampled population of beans)? After the P values for each class member have been tabulated on the board, answer the following question. 8) Why do the P values vary within the class when the actual ratio of beans is 1:1:1:1?Explanation / Answer
(7 and 8)
Since the p-value for observed chi-square value of 13.28 is less than 0.05, we consider this value as significant. Therefore we reject the null hypothesis and accept the alternate hypothesis. This means there is a significant difference between observed and expected frequencies, therefore the allies for the colour of beans are linked. Linked genes tend to be inherited together because they are located on the same chromosome, as a result, they do not follow Mendelian ratio.