I only need help understanding why the answer for #16 is A. A particle moves alo
ID: 2834502 • Letter: I
Question
I only need help understanding why the answer for #16 is A.
A particle moves along the x-axis and its position at time = t is given by the function s(t), where positive values of s indicate that the particle is to the right of zero. For example, s(2) = 3 indicates that at t =2, the particle is 3 units to the right of zero. Below you are given a graph of v(t), the particle's velocity at time = t. Use the graph to answer the questions that follow. For what values of t is the particle's velocity increasing? Circle the correct answer choice. For what values of t is the particle's acceleration negative? Circle the correct answer choice. For what values of t is the particle moving to the light? Circle the correct answer choice.Explanation / Answer
if s(t) is the displacement function then v(t) is d(s)/dt
as we can see from the plot that v(t) is never negative and also time cannot be negaative this means that change in displacement over the time is always positive, only difference is that in different intervals it varies differently but it is never negative. So if it moves right it always moves right over the journey i.e. from t>0.
so option A is correct