Part #3 : Feb 10, 2018 Illinois Winter Storm On Feb 10, 2018, Illinois saw a wid
ID: 287623 • Letter: P
Question
Part #3 : Feb 10, 2018 Illinois Winter Storm On Feb 10, 2018, Illinois saw a wide range of winter weather conditions due to a winter storm passing over the state Chicago got a foot of snow (shutting parts of the city down). The U of I had to deal with a couple of inches of sleet. St. Louis saw over 1/10th of an inch of freezing rain (causing numerous car accidents), while far Southern Illinois received a lot of rain. The image below shows 4 separate soundings that are each labeled with a letter. The solid black line on each sounding represents the temperature profile during the winter storm in Illinois on Feb 10, 2018. The red line represents the 0°C (32°F) isotherm. To the right of the red line, temperatures are above freczing and to the left, temperatures are below freezing. Match the sounding to the location based upon the description above. » 00-70 0 40 30 20 D1D 20 30 40 7D 0040 J0 -20 -10 10 20 30 4 80 70 50 4 30 20 10 20 30 40 Chicago Snow: C » U of I Sleet: B. St. Louis Freezing Rain: D Southern IL Rain: A The snowfall from the Feb 10, 2018 snowstorm covered most of IA, northern IL, northern IN, and southern MI While some locations in that snow swath saw over a foot of snow, let's assume the average depth of the snow over this area was 8 inches. If the total area covered by the 8 inch average depth was 69,250 square miles, what percentage of the volume of the Grand Canyon would this amount of snow fill? Show all ofyour work! Information vou need: - Area of snow cover: 69,250 miles2 Average depth of the snow over this region: 8 inches Volume of the Grand Canyon: 4.166*1012 meters3 » National Snowrall Analysis: 72 hour accumulation ending 2018 02 12 00 UTCExplanation / Answer
1 inch = 0.0254 meters
8 inches = 8 x 0.0254 meters = 0.2032 meters
1 miles2 = 2.59 x 106
69,250 miles2 = 69,250 x 2.59 x 106 = 1.793575 x 1011
Volume of ice = 1.793575 x 1011 x 0.2032 = 3.6445444 x 1010 m3
Volume of grand canyon = 4.166 x 1012 m3
Percentage of grand canyon's volume filled by snow = [(3.6445444 x 1010)/(4.166 x 1012)] x 100 = 0.874830 %