Congratulations, you have a summer internship with a medical equipment firm. You
ID: 2883249 • Letter: C
Question
Congratulations, you have a summer internship with a medical equipment firm. Your first assignment is to help design the mechanical lift that will move patients into position within a CAT scan system. Some of the main aims of the position control system in a lift are: To bring the patient to the correct height, To minimize travel time, To maximize patient comfort by providing a smooth ride, To accelerate, decelerate, and travel within safe speed limits. Assume for comfort a maximum acceleration of 0.8 m/s/s Two of your colleagues have suggested functions for the "flight path" where the vertical position s(t) (inches) with respect to time t (seconds) for 0Explanation / Answer
given
s1(t) = -0.00009t^4 + 0.0094t^3 -0.3703t^2 + 6.3723t
s2(t) = 0.00008t^4 - 0.0078t^3 + 0.2167t^2 - 0.2741t
now differentiating the functions
s1'(t) = -0.00036t^3 + 0.0282t^2 -0.7406t + 6.3723
s2'(t) = 0.00024t^3 - 0.0234t^2 + 0.4334t - 0.2741
now differential gives velocity
and the second differential gives accelration
s1''(t) = -0.00108t^2 + 0.0564t -0.7406
s2''(t) = 0.00072t^2 - 0.0468t + 0.4334
at t= 40 maximum accelration is given by
s1''(40) = -0.00108(40)^2 + 0.0564(40) -0.7406 = - 0.2162
s2''(40) = 0.00072(40)^2 - 0.0468(40) + 0.4334 = -0.2866
as shown the accelration of the second flight function is high which also indicates the better slopes and also in the range of maximum accelration so the better flight function is s2(t)