Today we will investigate how we may determine the nature of the original functi
ID: 2892825 • Letter: T
Question
Today we will investigate how we may determine the nature of the original function just from knowledge of the rate of change of the function. Recall: An equation of the form dy/dx = some expression is a differential equation if, upon appropriate substitution of the function and/or its derivative(s), the differential equation is true. a) Verity that y = x^3 + C is a solution for the differential equation dy/dx = 3x^2. b) verify further that y = x^3 + 4 is a solution the differential equation dy/dx = 3x^2 with y(0) = 4. Definitions: The statement y(0) = 4 is an initial condition, and the differential equation and the initial condition are together an initial-value problem.Explanation / Answer
From the given question,
part 1
a) dy/dx= 3x2
dy= 3x2 dx
integrating both sides
y= 3x3/3 +c
y=x3+c
Thus y=x3+c is a solution of differential equation dy/dx= 3x2
b) dy/dx= 3x2, y(0)=4
From the previous answer, y=x3+c
when x=0, y=4
4=03+c
c=4
rewriting the equation,y=x3+4
Hence y=x3+4 is solution of initial value, differential equation dy/dx= 3x2, y(0)=4.